Tuesday, 18th August, 2020 Chemistry 3 (Practical) (Alternative A) 9:30 am – 11;30 am ========================================
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That's why we post late and fade
WAEC-CHEMISTRY-PRACTICAL-ANSWERS
Pls use ur school end points.
(1a)
Burette reading (cm)³|1st reading|2na Reading|3rd reading|
Final |15.25|30.53|45.79|
Initial |0.00|15.25|30.53|
Volume of acids used |15.25|15.28|15.26
Average volume of acid used =15.25+15.26/2
=15.255cm³
=15.26cm³
Or =15.27cm³
(1b)
Given; mass con of A =5g/500cm³ = 5g/0.5dn³
CA=10g/dm³
A is HNO3
Therefore molar mass =1+14+(16*3)=15+48=63g/mol¹
Molarity of A = gram con/molar mass
CA=10/63=0.1587mol/dm3
(1bii)
Using CAVA/CBVB =Na/NB
With reacting equation ; HNO³ + NaOH---NaNO3+H2O
nA=1 nB=1
0.1587*15.26/CB*25.00=1/1
25CB=0.1587*15.26
CB=0.1587*15.26/25
CB=0.09687mol/dm³
(1biii)
B is NaOH
Molar mass
23+16+1=40g/mol
Conc of B in g/dm³=molarity * molar mass
= 0.09687*40
=3.8748g/dm³
(1biv)
No of moles present in 250cm³ of NaOH is =molar conc * volume
=0.09687*250/1000
=0.0242moles
Mole ratio of NaOH and NaNO3 is 1;1
No; of mole of NaNO3 which reacted is 0.0242
Mass of NaNO3 formed =molar mass * no; of moles
=85*0.0242
=2.05grams
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(2a)
TEST: C+burning splint
OBSERVATION: Sample C burst into flame .It burns with non smoky blue flame without soot. Colorless gas that turns wet blue litmus paper faint red and turns like water milky is present.
INFERENCE: C is volatile and flammable. The gas is CO2 from combustion of saturated organic compound.
(2bi)
TEST: C + distilled water + shake
OBSERVATION: Clear or colorless solution is observed
INFERENCE: C is miscible with water
(2bii)
TEST: C + Acidified K2Cr207
OBSERVATION: Orange color of K2Cr207 solution turns pale green and eventually pale blue on cooling
INFERENCE: C is a reducing agent
(2C)
TEST: D + C + 10% NaOH + Shake
OBSERVATION: D dissolves slowly in C and produces reddish brown solution. Reddish brown solution turns yellow precipitate. The precipitate has an antiseptic odour
INFERENCE: D is soluble in organic solvents
(2d)
Compound belongs to the class of secondary alkanol
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(3ai)
Zinc nitrate
(3aii)
2 Zn(NO 3 )2 ----->2 ZnO + 4 NO 2 + O 2
(3aiii)
It turns white when cold from it yellow colour when it was hot
(3b)
Pipette / measure 50.0cm3 of the stock solution into a 250
cm3 volumetric flask (containing some distilled water). Shake / swirl and add more distilled water until the mark is reached.
(3c)
Al2(SO4)3 - turns blue litmus red
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Complete.
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Pls use ur school end points.
(1a)
Burette reading (cm)³|1st reading|2na Reading|3rd reading|
Final |15.25|30.53|45.79|
Initial |0.00|15.25|30.53|
Volume of acids used |15.25|15.28|15.26
Average volume of acid used =15.25+15.26/2
=15.255cm³
=15.26cm³
Or =15.27cm³
(1b)
Given; mass con of A =5g/500cm³ = 5g/0.5dn³
CA=10g/dm³
A is HNO3
Therefore molar mass =1+14+(16*3)=15+48=63g/mol¹
Molarity of A = gram con/molar mass
CA=10/63=0.1587mol/dm3
(1bii)
Using CAVA/CBVB =Na/NB
With reacting equation ; HNO³ + NaOH---NaNO3+H2O
nA=1 nB=1
0.1587*15.26/CB*25.00=1/1
25CB=0.1587*15.26
CB=0.1587*15.26/25
CB=0.09687mol/dm³
(1biii)
B is NaOH
Molar mass
23+16+1=40g/mol
Conc of B in g/dm³=molarity * molar mass
= 0.09687*40
=3.8748g/dm³
(1biv)
No of moles present in 250cm³ of NaOH is =molar conc * volume
=0.09687*250/1000
=0.0242moles
Mole ratio of NaOH and NaNO3 is 1;1
No; of mole of NaNO3 which reacted is 0.0242
Mass of NaNO3 formed =molar mass * no; of moles
=85*0.0242
=2.05grams
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(2a)
TEST: C+burning splint
OBSERVATION: Sample C burst into flame .It burns with non smoky blue flame without soot. Colorless gas that turns wet blue litmus paper faint red and turns like water milky is present.
INFERENCE: C is volatile and flammable. The gas is CO2 from combustion of saturated organic compound.
(2bi)
TEST: C + distilled water + shake
OBSERVATION: Clear or colorless solution is observed
INFERENCE: C is miscible with water
(2bii)
TEST: C + Acidified K2Cr207
OBSERVATION: Orange color of K2Cr207 solution turns pale green and eventually pale blue on cooling
INFERENCE: C is a reducing agent
(2C)
TEST: D + C + 10% NaOH + Shake
OBSERVATION: D dissolves slowly in C and produces reddish brown solution. Reddish brown solution turns yellow precipitate. The precipitate has an antiseptic odour
INFERENCE: D is soluble in organic solvents
(2d)
Compound belongs to the class of secondary alkanol
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(3ai)
Zinc nitrate
(3aii)
2 Zn(NO 3 )2 ----->2 ZnO + 4 NO 2 + O 2
(3aiii)
It turns white when cold from it yellow colour when it was hot
(3b)
Pipette / measure 50.0cm3 of the stock solution into a 250
cm3 volumetric flask (containing some distilled water). Shake / swirl and add more distilled water until the mark is reached.
(3c)
Al2(SO4)3 - turns blue litmus red
=====================================
Complete.
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